searchInRotatedSortedArray.java

// Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

// (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

// You are given a target value to search. If found in the array return its index, otherwise return -1.

// You may assume no duplicate exists in the array.

public class Solution {

    public int search(int[] nums, int target) {
        
        int left = 0;
        int right = nums.length - 1;
        
        while(left <= right) {
            
            int mid = left + (right - left) / 2;
            
            if(nums[mid] == target) return mid;
            
            if(nums[left] <= nums[mid]) {
                
                if(target < nums[mid] && target >= nums[left])
                    right = mid - 1;
                else
                    left = mid + 1;
                    
            }
            
            if(nums[mid] <= nums[right]) {
                
                if(target > nums[mid] && target <= nums[right])
                    left = mid + 1;
                else
                    right = mid - 1;
                
            }
            
        }
        
        return -1;
        
    }

}