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/** | ||
* Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. | ||
* | ||
* Each number in C may only be used once in the combination. | ||
* | ||
* Note: | ||
* | ||
* All numbers (including target) will be positive integers. | ||
* | ||
* Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak). | ||
* The solution set must not contain duplicate combinations. | ||
* For example, given candidate set 10,1,2,7,6,1,5 and target 8, A solution set is: | ||
* [1, 7] | ||
* [1, 2, 5] | ||
* [2, 6] | ||
* [1, 1, 6] | ||
*/ | ||
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import java.util.ArrayList; | ||
import java.util.Arrays; | ||
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public class CombinationSumII { | ||
public ArrayList<ArrayList<Integer>> combinationSum2(int[] candidates, | ||
int target) { | ||
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>(); | ||
ArrayList<Integer> list = new ArrayList<Integer>(); | ||
Arrays.sort(candidates); | ||
dfs(res, 0, candidates, list, target); | ||
return res; | ||
} | ||
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private void dfs(ArrayList<ArrayList<Integer>> res, int start, | ||
int[] candidates, ArrayList<Integer> list, int target) { | ||
if (target == 0) { | ||
res.add(new ArrayList<Integer>(list)); | ||
return; | ||
} | ||
int pre = -1; | ||
for (int i = start; i < candidates.length; i++) { | ||
if (pre == candidates[i]) | ||
continue; | ||
if (candidates[i] > target) | ||
return; | ||
pre = candidates[i]; | ||
list.add(candidates[i]); | ||
dfs(res, i + 1, candidates, list, target - candidates[i]); | ||
list.remove(list.size() - 1); | ||
} | ||
} | ||
} |