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/** | ||
* Follow up for "Unique Paths": | ||
* | ||
* Now consider if some obstacles are added to the grids. How many unique paths would there be? | ||
* | ||
* An obstacle and empty space is marked as 1 and 0 respectively in the grid. | ||
* | ||
* For example, | ||
* There is one obstacle in the middle of a 3x3 grid as illustrated below. | ||
* | ||
* [ | ||
* [0,0,0], | ||
* [0,1,0], | ||
* [0,0,0] | ||
* ] | ||
* | ||
* The total number of unique paths is 2. | ||
* | ||
* Note: m and n will be at most 100. | ||
* | ||
*/ | ||
public class UniquePathsII { | ||
public int uniquePathsWithObstacles(int[][] obstacleGrid) { | ||
int m = obstacleGrid.length; | ||
if (m == 0) | ||
return 0; | ||
int n = obstacleGrid[0].length; | ||
int[][] map = new int[m][n]; | ||
map[0][0] = obstacleGrid[0][0] == 1 ? 0 : 1; | ||
for (int i = 1; i < m; i++) { | ||
map[i][0] = obstacleGrid[i][0] == 1 ? 0 : map[i - 1][0]; | ||
} | ||
for (int j = 1; j < n; j++) { | ||
map[0][j] = obstacleGrid[0][j] == 1 ? 0 : map[0][j - 1]; | ||
} | ||
for (int i = 1; i < m; i++) { | ||
for (int j = 1; j < n; j++) { | ||
map[i][j] = obstacleGrid[i][j] == 1 ? 0 : map[i - 1][j] | ||
+ map[i][j - 1]; | ||
} | ||
} | ||
return map[m - 1][n - 1]; | ||
} | ||
} |